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Old 06-05-2005, 09:22 PM
honki24 honki24 is offline
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Join Date: May 2005
Posts: 6
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k... lets see... 3.9 gal = 14763 cc ...therefore... 3.9gal/min WI should mean I am injecting 14763cc/min. In one rotation there is 4 ignitions, meaning 2200cc per rotation. if I'm at say 6K rpm... then I have 13,200,000cc per minute of fuel. and 14763cc per minute of water. that means I am running .1118% water to fuel? did I do that right?
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