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Originally Posted by Forum Admin
It is difficult to arise at a stoichmetric ratio betwen fuel and gasoline when the alcohol is at a fix ratio to fuel (it can be calculated).
At rich air fuel ratio, all liquid acted as a coolant when oxygen is fully consummed. But at lean air/fuel ratio, alcohol becomes a high octane fuel rather a coolant.
We need to define what portion of fuel is used for combustion across the plot, with the exception of water, air/fuel/methanol is still any unknown variable.
I suppose the details doesn't really matter as long as it produced a repeatable result.
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Since this methanol was injected at essentially the same location as the fuel, and by the same method, it may as well have been mixed with the fuel.
Therefore I think it would be reasonable to use the "blending octane" listed for Methanol:
(Different from the straight octane. These are used when Methanol is blended with other fuels, which is essentially what is happening in this case.)
RON: 133
MON: 105
The blending octane for methanol should
very accurately describe the effects of the methanol on octane given the method for injection.
The only variable now is the octane of the AN-F-28 Aviation fuel used in the study.
Also it should be noted that the consumption of methanol relative to fuel does not increase in the lean region, therefore if you have sufficient air you might find that running lean with a high meth/water injection level could allow for serious amounts of power without running a huge fuel tank for the methanol.
Adrian~