real numbers
Leaving aside all the other issues lets look at the real world numbers.
people sometimes forget just how small milligrams/liter is.
Assuming you are achieving the 80 milligram / liter of disolved oxygen mentioned in that paper (which is the upper limit claimed).
You have a 400 hp engine, and you run the 1/4 mile in 13 seconds flat. You are injecting pure superoxygenated water at a rate of 500 cc/min.
Your engine will process a maximum of 42 lbs/min of air as it moves down the 1/4 mile. In the 13 seconds of the run that comes out to 42 x .02316 = 9.7272 lb O2, or 4416.1488 grams of O2.
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Correction in the above I forgot to reduce the air flow to the fraction consumed in 13 seconds as stated. Formula should have been:
42 lb air / min x .02316 lb O2/lb air = 9.7272 lb O2/min. 13 seconds of consumtion at this rate equals ( 13/60 ) x 9.7272 lb O2/ min = 2.10756 lb O2/ run , or 956.83224 grams of O2.
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Meanwhile your WI is injecting 500 cc of water / min or 108.33 cc of water. This equals 0.10833 Liters, at 80 mg/liter you have added 8.666 mg of additional oxygen to the 4416.1488 that is in the air.
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Correction the above should read
Meanwhile your WI is injecting 500 cc of water / min or 108.33 cc of water. This equals 0.10833 Liters, at 80 mg/liter you have added 8.666 mg of additional oxygen to the 956.83224 that is in the air.
You have increased the engines oxygen intake by 0.0001962 %.
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The above should read:
(956.83224 + .008666)/956.83224 = 956.840906/956.83224 = 1.000009057 or 0.000957 %
You have increased the engines oxygen intake by 0.000957 %.
400 hp x .000009057 = 0.003622788 hp
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Since one cubic foot of air holds about 0.016212 lb of O2, or 0.000009382 lb/ cubic inch or .0042594 gm of O2 per cubic inch, your additional .008666 gram of dissolved O2 is approximately equal to the oxygen contained in one half of a cubic inch of air.
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The above should be corrected to:
Since one cubic foot of air holds about 0.016212 lb of O2, or 7.360248 gm / cubic ft or 0.004259403 gm/ cubic inch , your additional .008666 gram of dissolved O2 is approximately equal to the oxygen contained in 2.03 cubic inches of air.
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And that is a best case scenario.
I think I'll just stick with plain cold water and not worry about dissolved oxygen content.
Larry
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