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Originally Posted by hotrod
Leaving aside all the other issues lets look at the real world numbers.
people sometimes forget just how small milligrams/liter is.
Assuming you are achieving the 80 milligram / liter of disolved oxygen mentioned in that paper (which is the upper limit claimed).
You have a 400 hp engine, and you run the 1/4 mile in 13 seconds flat. You are injecting pure superoxygenated water at a rate of 500 cc/min.
Your engine will process a maximum of 42 lbs/min of air as it moves down the 1/4 mile. In the 13 seconds of the run that comes out to 42 x .02316 = 9.7272 lb O2, or 4416.1488 grams of O2.
Meanwhile your WI is injecting 500 cc of water / min or 108.33 cc of water. This equals 0.10833 Liters, at 80 mg/liter you have added 8.666 mg of additional oxygen to the 4416.1488 that is in the air.
You have increased the engines oxygen intake by 0.0001962 %.
Since one cubic foot of air holds about 0.016212 lb of O2, or 0.000009382 lb/ cubic inch or .0042594 gm of O2 per cubic inch, your additional .008666 gram of dissolved O2 is approximately equal to the oxygen contained in one half of a cubic inch of air.
And that is a best case scenario.
I think I'll just stick with plain cold water and not worry about dissolved oxygen content.
Larry
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I read your calculation with interest, couldn't quite get the correct % of oxygen increase by mass.
4400g of oxygen injected against 80mg/litre/min (40mg/500ml/min). The % of oxygen is 40/4400 = 0.9%, for a 400BHP engine, 1% extra oxygen is 4 BHP - is small but an significant increase?