Post Combustion injection of water

[tawnybill]

You've got it !

This is derived from ,
1 btu = raising 1 pound of water 1 degree F + the latent heat of evaporation of 960btu = (or about) 1140btu/pound from water to steam (180 btu+960 btu = 1140) and with about 140,000 btu/gallon of fuel available, it could evaporate (140,000 divided by 1140= 122.8 lbs of water or) more than 10 gallons of water to steam.

Allowing for heat losses and the effect of the cylinder pressure on the charge of steam, it results in a superheated volume of relatively dry steam. (this will help in clearing all of the steam out on the opening of the exhaust valve and drying out the cylinder) simple eh? :?

Wil'